This Bash script takes three command-line arguments and prints each one to the console on a separate line.

Run example

npm run import -- "test command arguments"

test command arguments

echo "$1"
echo "$2"
echo "$3"

#!/bin/bash

display_arguments() {
  # Check if the correct number of arguments are provided
  if [ $# -ne 3 ]; then
    echo "Error: Exactly 3 arguments are required."
    return 1
  fi

  # Display the command line arguments
  for ((i=1; i<=$#; i++)); do
    echo "Argument $i: ${!i}"
  done
}

display_arguments "$1" "$2" "$3"

This code snippet simply prints the values of three command-line arguments to the console.

Here's a breakdown:

1. echo "$1": Prints the value of the first command-line argument ($1).
2. echo "$2": Prints the value of the second command-line argument.

echo "$3": Prints the value of the third command-line argument.

Explanation:

• echo: This is a command in Unix-like operating systems that prints its arguments to the standard output (usually the console).
• "$1", "$2", "$3": These are variables that represent the command-line arguments passed to the script.
  • $1 refers to the first argument.
  • $2 refers to the second argument.
  • $3 refers to the third argument.
  • The double quotes (") around the variables are important because they ensure that any spaces or special characters within the arguments are treated as part of the argument itself.

How it works:

When you run this script, you need to provide at least three arguments after the script name. For example:

./script.sh hello world example

The script will then print the following output:

hello
world
example

Let me know if you have any other code snippets you'd like me to explain!